2025 UPDATED!!! Which polynomial has (3x + 2) as a binomial factor? 6x3 + 3x2 + 4x + 2 12x2 + 15x + 8x + 10 18x3 – 12x2 + 9x

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Which polynomial has (3x + 2) as a binomial factor?

6×3 + 3×2 + 4x + 2
12×2 + 15x + 8x + 10
18×3 – 12×2 + 9x – 6
21×4 + 7×3 + 6x + 2

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If binomial (3x + 2) is a factor of polarization division, then number $x = - dfrac {2} {3}$ this is the root of this polymy. Check all polynomials:

A. For the polymy 6x ^ 3 + 3x ^ 2 + 4x + 2,

$6 left (- dfrac {2} {3} right) ^ 3 + 3 left (- dfrac {2} {3} right) ^ 2 + 4 left (- dfrac {2 } {3} right) + 2 = - dfrac {16} {9} + dfrac {4} {3} - dfrac {8} {3} +2 = - dfrac {10} {9} neq 0.$

B. For the polymy 12x ^ 2 + 15x + 8x + 10,

$12 left (- dfrac {2} {3} right) ^ 2 + 23 left (- dfrac {2} {3} right) + 10 = dfrac {16} {3} - dfrac {46} {3} + 10 = 0.$

C. For the polymy 18x ^ 3-12x ^ 2 + 9x-6,

$18 left (- dfrac {2} {3} right) ^ 3 -12 left (- dfrac {2} {3} right) ^ 2 + 9 left (- dfrac {2 } {3} deas) -6 = - dfrac {16} {3} - dfrac {16} {3} -6-6 neq 0.$

D. For the polymy 21x ^ 4 + 7x ^ 3 + 6x + 2,

$21 left (- dfrac {2} {3} right) ^ 4 +7 left (- dfrac {2} {3} right) ^ 3 +6 left (- dfrac {2 } {3} deas) + 2 = dfrac {112} {27} - dfrac {56} {27} -4 + 2 neq 0.$

B is the correct choice

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