2024 UPDATED!!! Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?

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Which of the following represents the zeros of f(x) = 2×3 − 5×2 − 28x + 15?

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B) are 5, −3, 1 over 2 zeros f (x).

Step by step explanation:

Give function f (x) = 2x ^ 3-5x ^ 2-28x + 15

If a is zero f (x), then f (a) = 0

Let’s check each option

$f (5) = 2 (5) ^ 3-5 (5) ^ 2-28 (5) +15 \ = 2 (125) -5 (25) -28 (5) + 15 = 250-125-140 + 15 = 0$

$f (-3) = 2 (-3) ^ 3-5 (-3) ^ 2-28 (-3) +15 \ = 2 (-27) -5 (9) -28 (-3) +15 = -54-45 + 84 + 15 = 0$

$f ( frac {-1} {2}) = 2 frac {-1} {2} () ^ 3-5 ( frac {-1} {2}) ^ 2-28 ( frac {-1 } {2}) + 15 \ = 2 ( frac {-1} {8}) - 5 ( frac {-1} {4}) + 14 + 15 = frac {-1} {4} - frac {5} {4} + 29 = frac {110} {4} = frac {55} {2} neq 0$

Thus, 5 and -3 are zeros of 5 (x). Bb -1/2 does not equal.

$f ( frac {1} {2}) = 2 frac {1} {2} () ^ 3-5 ( frac {1} {2}) ^ 2-28 ( frac {1} {2} ) +15 \ = 2 ( frac {1} {8}) - 5 ( frac {1} {4}) - 14 + 15 = frac {1} {4} - frac {5} {4 } -14 + 15 = 0$

The third zero of f (x) is ⇒ 1/2.

Here we find our three zeros as 5, -3,1 / 2, others will not satisfy f (a) = 0

Thus B equals zero f (x).

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