Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nc . part a what is the electric field strength inside the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part b what is potential difference across the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer part c what is the electric field strength inside the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part d what is the potential difference across the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer provide feedback next

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Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nc . part a what is the electric field strength inside the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part b what is potential difference across the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer part c what is the electric field strength inside the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part d what is the potential difference across the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer provide feedback next

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A.

B. 151.2 V.

C.

D. V = 302.4 V.

Solution:

By question:

Plate area of ​​parallel plate capacitors,

Charge on capacitor plates,

Now,

(A) To calculate the strength of the electric field, E when the distance is divided, d = 1.00 mm = :

(B) To calculate a potential difference between the plates:

(C) The electric field strength when the spacing is 2 mm, ie, :

Since then, the above expression of the electric field shows that it does not depend on the separation distance between the plates so it will remain the same, ie,

(D) Possible difference across capacitor when :

V = Ed =