THIS USER ASKED ๐
The product of two consecutive negative integers is 600. what is the value of the lesser integer?
THIS IS THE BEST ANSWER ๐
N and n + 1 are two consecutive negative integers. We say that these two integers are 600 products:
n (n + 1) = 600
n ^ 2 + n = 600
n ^ 2 + n-600 = 0
n ^ 2 + 25n-24n-600 = 0
n (n + 25) -24 (n + 25) = 0
(n-24) (n + 25) = 0, since we are told that n is negative …
n = -25
(…- 25 (-24) = 600 so -25 is the value of the smallest integer)
Leave a Reply