SOMEONE ASKED 👇
The intensity of sunlight at the Earth’s distance from the Sun is 1370 W/m2.?
HERE THE ANSWERS 👇

1370 W/m^2 is the intensity of sunlight reaching the earth, and is the value of the Poynting vector at the top of the earth’s atmosphere. The pressure exerted by this radiation is Intensity/c where c is the speed of light.
Check units: W/m^2 = Js^(1) m^(2)
J= N m =>W/m^2= Js^(1)m^(2)=Nm^(1)s^(1)
so W/m^2/(m/s) = Nm^(1)s^(1)/ms^(1) = Nm^(2) = pressure
so we have verified that the units of intensity/speed of light = units of radiation pressure
therefore, the force of radiation acting on the earth is:
force = radiation pressure x area = (intensity/c)xpi R^2
force = 1370W/m^2 x pi x( 6.37×10^6m)^2/3×10^8m/s
force = 5.82×10^8 N
I am presuming that the sun’s gravitational attraction means the magnitude of the solar gravitational force on earth: If that’s the case, the answer is approx 10^22 N:
F=GMm/r^2
G=6.67×10^(11)=6.67e11
M=mass sun = 2×10^30kg=2e30
m=mass earth = 6×10^24kg
r=earth sun distance = 1.5×10^11m
F=(6.6e11)(2e30)(6e24)/(1.5e11)^2 = 3.56e22N

78 min. (fyi) the variation in time is due to eliptical orbit of earth

“power=IA=pi (radius earth)^(2)(1370w/m2)=5.82e8 newtons” ??
If you work it out it comes in Watts. Power is measured in Watt not Newton.
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