The endpoints of `bar(ef)` are e(xe , ye) and f(xf , yf). what are the coordinates of the midpoint of `bar(ef)`? a. `((x_f)/()/(2))` b. `((x_e)/()/(2))` c. `((x_e+x_f)/(+y_f)/(2))` d. `(x_e+(x_f)/(2),y_e+(y_f)/(2))`

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The endpoints of `bar(ef)` are e(xe , ye) and f(xf , yf). what are the coordinates of the midpoint of `bar(ef)`? a. `((x_f)/()/(2))` b. `((x_e)/()/(2))` c. `((x_e+x_f)/(+y_f)/(2))` d. `(x_e+(x_f)/(2),y_e+(y_f)/(2))`

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To better understand the solution provided here find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment are always the coordinates of the endpoints of that line segment.

So if, for example, the end coordinates are a line segment and then the coordinates of the midpoint of this line segment are the mean coordinates of the two endpoints and will therefore be:

So for our questions are the endpoints and so the midpoint will be:

So Option C is the right choice.