Ican’t remember how to calculate this. match the object positions with the image positions for a convex lens. (4 points)

THIS USER ASKED 👇

Ican’t remember how to calculate this. match the object positions with the image positions for a convex lens. (4 points)

THIS IS THE BEST ANSWER 👇

You need to draw two lines from the end of the arrow: one parallel to the axis (which will be bent) and the other passing through the center of the convergence lens (which will continue straight) and see where they intersect.

If the arrow is at an infinite distance, the image will look like a point in F.
If the arrow is longer than 2F, the image will be upside down between F and 2F.
If the arrow is at a distance of 2F, the image will be upside down in 2F.
If the arrow distance is between F and 2F, the upside-down image will be longer than 2F.
If the arrow is at distance F, all the rays go parallel to each other and no image is created.
If the arrow is at a distance less than F, the image will be virtual.

Thus, the correct games are 1B, 2C, 3D, and 4A.