What is the x component of the resultant force?
SOMEONE ASKED π
What is the x component of the resultant force?
HERE THE ANSWERS π

F1) Y = SIN 62 * 8.8 N = 7.77 , X = COS 62 * 8.8 N = 4.13
F2) Y = SIN 53.5 * 7 N = 5.63, X = COS 53.5 * 7N = 4.16
Result = Y = 7.77 + β 5.63 = + 2.14, and X = 4.13 + 4.16 = 8.29
= SQRT (2.14^2 + 8.29^2) = 8.56 N magnitude
r =8.56N @ ARC TAN 2.14 / 8.29 = 14.47 deg above the Negative X axis.

Draw a diagram. Use it to get the +/ signs for each component.
Total of xcomponents is X where:
X = (8.80cos(62β°)) + (7.00cos(53.5β°))
Total of ycomponents is Y where:
Y = (+8.80sin(62β°)) + (7.00sin(53.5β°))
R =β(XΒ² + YΒ²)
But youβll have to do the arithmetic!
The first videolesson below explains how to work out components.
The second videolesson below explains how to use components.
Though the contents of the videos overlap.