What is the x component of the resultant force?

Bysoetrust

SOMEONE ASKED 👇

What is the x component of the resultant force?

HERE THE ANSWERS 👇

  • F1) Y = SIN 62 * 8.8 N = 7.77 , -X = COS 62 * 8.8 N = -4.13

    F2) -Y = SIN 53.5 * 7 N = -5.63, -X = COS 53.5 * 7N = -4.16

    Result = Y = 7.77 + – 5.63 = + 2.14, and X = -4.13 + -4.16 = -8.29

    = SQRT (2.14^2 + 8.29^2) = 8.56 N magnitude

    r =8.56N @ ARC TAN 2.14 / 8.29 = 14.47 deg above the Negative X axis.

  • Draw a diagram. Use it to get the +/- signs for each component.

    Total of x-components is X where:

    X = (-8.80cos(62⁰)) + (-7.00cos(53.5⁰))

    Total of y-components is Y where:

    Y = (+8.80sin(62⁰)) + (-7.00sin(53.5⁰))

    ||R|| =√(X² + Y²)

    But you’ll have to do the arithmetic!

    The first video-lesson below explains how to work out components.

    The second video-lesson below explains how to use components.

    Though the contents of the videos overlap.

    Source(s): http://www.youtube.com/watch?v=OBaCUYBdFs8
    http://www.youtube.com/watch?v=eIYJSHlH4TE

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