What is her speed at the bottom of the slope?

SOMEONE ASKED 👇

What is her speed at the bottom of the slope?

HERE THE ANSWERS 👇

  • Θ = arcsin(30/410) = 4.2º

    weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

    friction upslope = 15 N

    net downslope force = 35.2 N, so

    net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

    Now use Torricelli’s equation:

    v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

    v = 23 m/s

    Hope this helps!

  • A steady 15N drag force due to air resistance acts on her –that isn;t how it works

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What is her speed at the bottom of the slope?

SOMEONE ASKED 👇

What is her speed at the bottom of the slope?

HERE THE ANSWERS 👇

  • Θ = arcsin(30/410) = 4.2º

    weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

    friction upslope = 15 N

    net downslope force = 35.2 N, so

    net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

    Now use Torricelli’s equation:

    v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

    v = 23 m/s

    Hope this helps!

  • A steady 15N drag force due to air resistance acts on her –that isn;t how it works

Similar Posts

Leave a Reply

Your email address will not be published.

What is her speed at the bottom of the slope?

SOMEONE ASKED 👇

What is her speed at the bottom of the slope?

HERE THE ANSWERS 👇

  • Θ = arcsin(30/410) = 4.2º

    weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

    friction upslope = 15 N

    net downslope force = 35.2 N, so

    net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

    Now use Torricelli’s equation:

    v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

    v = 23 m/s

    Hope this helps!

  • A steady 15N drag force due to air resistance acts on her –that isn;t how it works

Similar Posts

Leave a Reply

Your email address will not be published.