# What is her speed at the bottom of the slope?

What is her speed at the bottom of the slope?

• Θ = arcsin(30/410) = 4.2º

weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

friction upslope = 15 N

net downslope force = 35.2 N, so

net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

Now use Torricelli’s equation:

v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

v = 23 m/s

Hope this helps!

• A steady 15N drag force due to air resistance acts on her –that isn;t how it works

# What is her speed at the bottom of the slope?

What is her speed at the bottom of the slope?

• Θ = arcsin(30/410) = 4.2º

weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

friction upslope = 15 N

net downslope force = 35.2 N, so

net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

Now use Torricelli’s equation:

v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

v = 23 m/s

Hope this helps!

• A steady 15N drag force due to air resistance acts on her –that isn;t how it works

# What is her speed at the bottom of the slope?

What is her speed at the bottom of the slope?

• Θ = arcsin(30/410) = 4.2º

weight downslope = mgsinΘ = 70kg 9.8m/s² sin4.2 = 50.2 N

friction upslope = 15 N

net downslope force = 35.2 N, so

net downslope acceleration = 35.2N / 70kg = 0.50 m/s²

Now use Torricelli’s equation:

v² = u² + 2as = (11m/s)² + 2 0.50m/s² 410m = 533 m²/s²

v = 23 m/s

Hope this helps!

• A steady 15N drag force due to air resistance acts on her –that isn;t how it works