Torque problems or something of the sort, PHYSICS?

SOMEONE ASKED πŸ‘‡

Torque problems or something of the sort, PHYSICS?

HERE THE ANSWERS πŸ‘‡

  • Working from the centre, torque right side = (4kg. x .5m) + (1.2kg x .5m), = 2.6kg/m.

    Torque left = (1.2 x .5) = 0.6kg/m.

    Ratio of torques = (2.6/0.6).

    Position for fulcrum for balance = 2m/((2.6/.6) + 1), = 0.375m. from the right end, so

    D = (2 – 0.375) = 1.625 metres.

Similar Posts

Leave a Reply

Your email address will not be published.