Steelhead trout migrate upriver to spawn.?
SOMEONE ASKED π
Steelhead trout migrate upriver to spawn.?
HERE THE ANSWERS π

a/ OK
b/
the height h(t) = 4.9t^2 + 8t
h(t)=1.8 —> t = 0.3 or 1.4 seconds

Hmax = Voy^2/2g = 8^2/19.6 = 3.27 m
1.8 = 8*t4.9*t^2
t = (8β8^219.6*1.8)/9.8 = 0.27 sec
t = (8+β8^219.6*1.8)/9.8 = 1.36 sec
What’s the meaning of these two times?
With such an initial vertical speed (8.0 m/sec) , the steelhead reaches a top height of 3.27 m and then fall down , therefore the height of 1.8 m is met twice, the first time after 0.27 sec while ascending and the second while descending .
Since the motion can’t be stopped while ascending , it is reasonable to consider the longer time as the proper answer to such problem !!!