Solve the following inequality: 38 28 D. x > 4?
SOMEONE ASKED π
Solve the following inequality: 38 28 D. x > 4?
HERE THE ANSWERS π

Hi,
Solve the following inequality: 38 < 4x + 3 + 7 β 3x.
38 < 4x + 3 + 7 β 3x
38 < x + 10
28 < x, which is the same as x > 28 when it is reversed.
A. x < 28
B. x < 4
C. x > 28 <==ANSWER
D. x > 4
I hope that helps!! π

38 < 4x + 3 + 7 – 3x
28 < x
Answer choice:
C. x > 28

C, since you subtract both sides by 3 and 7 getting you 28<4x3x. This then leads you to find out that x>28 giving you the answer.

38 < 4x + 3 + 7 β 3x
38 < 4x + 10 – 3x
28 < x (A)
Maybe you ask your teacher if it is correct.

23x^2 – 69x = 23x(x3) #22 If the made of two components is 0, which of here won’t be able to be genuine? A.) the two components are no longer 0 is fake. a million ingredient must be 0. #23 ingredient: X^2 – 7x 12 (x3)(x4) #24 ingredient: x^2 6x – 7 (x+7)(xa million) #25 ingredient: x^2 – 4x – 32 (x8)(x+4) #30 Use removal to sparkling up the device of equations: x+ 2y = 18 x + 8y = 38 upload the two eqs 0 + 10y = 20 y= 20 #31 ingredient: x^2 13x 40 two seem lower back at those i’ve got already performed and parent this one out #32 sparkling up: x^2 5x – 14 = 0 (ingredient this one, think of 7 and a couple of) #33 sparkling up here: (q 2)^2 = 25 take the squarert of the two facets #34 sparkling up here: y^2 6y 9 = 40 9 subtract 40 9 from the two facets and then ingredient like above