SOMEONE ASKED 👇
Prove or disprove that if a and b are rational numbers, then a^b is also rational. ?
HERE THE ANSWERS 👇
Proof by counter-example:
Let a = 3 and b = 1/2, therefore a^b is the square root of 3, which can’t be written as a ratio of two whole numbers, and is therefore irrational.
let a = 2 and b = 1/2
a^b = 2^(1/2) = sqrt(2) which is not a rational number
Therefore the statement is false
Let a=2, b=1/2, both rational.
a^b = 2^(1/2)= sqrt 2 which is irrational.
yesSource(s): Now answer my question…