SOMEONE ASKED 👇
How many photons are contained in a flash of green light (525 nm) that contains 189 kJ of energy?
HERE THE ANSWERS 👇
Energy per photon: Ep=hc/L (L=wavelength, h=Planck’s constant)
Number of photons, E/Ep=EL/hc=189kJ252nm/(h*c) = 2.39764982 × 10^23Source(s): Studied physics; used Google to do calculation.
First consider the equation E=hc/(wavelength or Lambda)
H= planck s constant of 6.626×10^-34 J*s
c = 3.0×10^8 m/s
Lambda is given to you at 525 nm or 525×10^-9
so the equation is set up as follows:
(6.626×10^-34 J*S)(3.0×10^8 m/s) / 525×10^-9 nm = 3.79X10^-19 Joules PER photon
next you divide the joules per photon by the total energy of 189kj given
189000 / 3.79×10^-19 = 4.99×10^-23 photons.Source(s): Taking Chemistry right now. same section
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