Calculate the standard enthalpy change of the reaction?

SOMEONE ASKED 👇

Calculate the standard enthalpy change of the reaction?

HERE THE ANSWERS 👇

  • I’ve only got parts A and B, as I’m not confident in identifying catalysts (part C).

    Part A

    Calculate the standard enthalpy change of the reaction

    ClO(g) + O3(g) → ClO2(g) + O2(g)

    ∆H°rxn = Σ [∆H°f products] – Σ [∆H°f reactants]

    = { [∆H°f ClO2(g)] + [∆H°f O2(g)] } – { [∆H°f ClO(g)] + [∆H°f O3(g)] }

    = [(102.0 kJ/mol) + (0 kJ/mol)] – [(101.0 kJ/mol) + (142.3 kJ/mol)]

    = (102.0 kJ/mol) – (243.3 kJ/mol)

    = -141.3 kJ/mol

    —-

    Part B

    Calculate the standard enthalpy change of the reaction

    ClO2(g) + O(g) → ClO(g) + O2(g)

    ∆H°rxn = Σ [∆H°f products] – Σ [∆H°f reactants]

    = { [∆H°f ClO(g)] + [∆H°f O2(g)] } – { [∆H°f ClO2(g)] + [∆H°f O(g)] }

    = [(101.0 kJ/mol) + (0 kJ/mol)] – [(102.0 kJ/mol) + (247.5 kJ/mol)]

    = (101.0 kJ/mol) – (349.5kJ/mol)

    = -248.5 kJ/mol

Similar Posts

Leave a Reply

Your email address will not be published.