Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced in the following:?

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Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced in the following:?

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  • there is a 3:1 ratio of Fe to Al2O3 so you can set up a proportion. Which would lead to you dividing .60mols of Fe by 3. Because for every 3 mols of Fe, 1 mole of Al2)3 is produced.

    Therefore, .6/3=.2 moles of al2O3

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    Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced in the following:?

    Calculate the number of moles of Al2O3 that are produced when 0.60 mol of Fe is produced in the following reaction: 2Al(s)+3FeO(s) = 3Fe(s)+Al2O3(s)

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    Thats an easy one. You just have to do a ratio. the ratio is 3 to one since for 3 moles of Fe you get 1 mole of Al2O3 so 1.8/3 = x/1 x=0.6

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  • .2moles of Al2O3

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