## THIS USER ASKED π

**Which second degree polynomial function f(x) has a lead coefficient of 3 and roots 4 and 1? f(x) = 3×2 + 5x + 4 f(x) = 3×2 + 15x + 12 f(x) = 3×2 β 5x + 4 f(x) = 3×2 β 15x + 12**

## THIS IS THE BEST ANSWER π

In this case we need the following function to meet the given conditions:

To prove it, let’s find the roots of the polymy:

By doing a common factor of 3 we need to:

Our second stage polypolytic factor:

Then, the solutions are:

Solution 1:

Solution 2:

A second-degree polymorphic function f (x) having a coefficient of lead 3 and roots 4 and 1 is: