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Which are the solutions of x2 = –13x – 4? 0, 13 0, –13

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You can rearrange the equation as x ^ 2 + 13x + 4 = 0

Quadratic equations as tua ^ 2 + bx + c = 0 we use the quadratic formula:

x_ {1,2} =  cfrac {-b  pm  sqrt {b ^ 2-4ac}} {2a}

In your case, a = 1, b = 13, c = 4, so the formula is made

x_ {1,2} =  cfrac {-13  pm  sqrt {169-16}} {2} =  cfrac {-13  pm  sqrt {153}} {2}

So there are both solutions

x =  cfrac {-13+  sqrt {153}} {2}  text {or} x =  cfrac {-13-  sqrt {153}} {2}