## THIS USER ASKED π

**What is the maximum value of p = 4x + 2y, given the constraints on x and y listed below? x+ 2y < 10 ys2 x20 y20**

## THIS IS THE BEST ANSWER π

P <28

Step by step explanation:

in view of the restrictions:

x + 2y <10

y <2

x> 0

y> 0

we can see that y ranges from 0 to 2:

we can use the maximum value of ya in x + 2y <10, to find the range of xa

x + 2y <10

x + 2 (2) <10

x <10 -4

x <6

now we know that x ranges from 0 to 6:

take a closer look at these ranges, both x and ya ranges do not include real values. (these are not )

The function of P is:

P = 4x + 2y, we can put all the maximum ranges x and y into the equation to get the maximum value of P. but before plugging in the values ββwe have to be careful: we are adding the ends of the ranges into the equation, but these extremes are not in the actual range itself.

so instead of writing that the maximum value of P is equal to a number, we should write that the maximum value of P is close to that number (or approaching that number from below)

P <4 (6) + 2 (2)

P <28

NOTE:

if the restrictions given include the ends of the ranges. Then the answer is P = 28.