## THIS USER ASKED ๐

**The system mx+ny=p has the solution (1,3), where rx+sy=t m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.**

## THIS IS THE BEST ANSWER ๐

Given:

The system has a resolution (1,3) of Mx + Ny = P where Rx + Sy = T; M, N, P, R, S and T are non-zero real numbers.

Solutions for M, N, R, P, S, T:

M + 3N = P.

R + 3S = T.

The options given should be simplified to the above equations.

A) Mx + Ny = P.

7Rx + 7Sy = 7T

7 (Rx + Sy) = 7T

Rx + Sy = T.

statements: RIGHT

B) (M + R) x + (N + S) y = P + T.

Rx + Sy = T.

Mx + Rx + Ny + Sy = P + T.

Mx + Ny + T = P + T.

Mx + Ny = P.

statements: RIGHT

C) Mx + Ny = P.

(2M – R) x + (2N – S) y = P – 2T

2Mx – Rx + 2Ny – Sy = P – 2T

2 (Mx + Ny) – (Rx + Sy) = P – 2T

2P – (Rx + Sy) = P – 2T

statements: INPUT