The system mx+ny=p has the solution (1,3), where rx+sy=t m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.
The system mx+ny=p has the solution (1,3), where rx+sy=t m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.
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Given:
The system has a resolution (1,3) of Mx + Ny = P where Rx + Sy = T; M, N, P, R, S and T are non-zero real numbers.
Solutions for M, N, R, P, S, T:
M + 3N = P. R + 3S = T.
The options given should be simplified to the above equations.
A) Mx + Ny = P. 7Rx + 7Sy = 7T 7 (Rx + Sy) = 7T Rx + Sy = T. statements: RIGHT
B) (M + R) x + (N + S) y = P + T. Rx + Sy = T. Mx + Rx + Ny + Sy = P + T. Mx + Ny + T = P + T. Mx + Ny = P. statements: RIGHT
C) Mx + Ny = P. (2M – R) x + (2N – S) y = P – 2T 2Mx – Rx + 2Ny – Sy = P – 2T 2 (Mx + Ny) – (Rx + Sy) = P – 2T 2P – (Rx + Sy) = P – 2T statements: INPUT
