The system mx+ny=p has the solution (1,3), where rx+sy=t m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.

THIS USER ASKED 👇

The system mx+ny=p has the solution (1,3), where rx+sy=t m, n,p, r,s and t are non zero real numbers. which of the following system would not have (1,3) as a solution.

THIS IS THE BEST ANSWER 👇

Given:

The system has a resolution (1,3) of Mx + Ny = P where Rx + Sy = T; M, N, P, R, S and T are non-zero real numbers.

Solutions for M, N, R, P, S, T:

M + 3N = P.
R + 3S = T.

The options given should be simplified to the above equations.

A) Mx + Ny = P.
7Rx + 7Sy = 7T
7 (Rx + Sy) = 7T
Rx + Sy = T.
statements: RIGHT

B) (M + R) x + (N + S) y = P + T.
Rx + Sy = T.
Mx + Rx + Ny + Sy = P + T.
Mx + Ny + T = P + T.
Mx + Ny = P.
statements: RIGHT

C) Mx + Ny = P.
(2M – R) x + (2N – S) y = P – 2T
2Mx – Rx + 2Ny – Sy = P – 2T
2 (Mx + Ny) – (Rx + Sy) = P – 2T
2P – (Rx + Sy) = P – 2T
statements: INPUT