## THIS USER ASKED 👇

**In which triangle is the value of x equal to cos−1(StartFraction 4.3 Over 6.7 EndFraction)?**

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**(Images may not be drawn to scale.)
A right triangle is shown. The length of the hypotenuse is 6.7 and the length of another side is 4.3. The angle between the 2 sides is x.
A right triangle is shown. The length of the hypotenuse is 6.7 and the length of another side is 4.3. The angle opposite to side with length 4.3 is x.
A right triangle is shown. The length of the hypotenuse is 4.3 and the length of another side is 6.7. The angle between 2 sides is x.
A right triangle is shown. The length of the 2 sides are 6.7 and 4.3. The angle opposite to side with length 4.3 is x.**

## THIS IS THE BEST ANSWER 👇

The square is 731

Step by step explanation:

Let me try … 13, 1 + 35 + 7, 1 + 3 + 57 + 9 + 11, 1 + 3 + 5 + 79 + 11 + 13 + 15 … (1)

grab the prime number in each sequence: 13,35,57,79,911,1113

There is another arithmetic sequence: 1, 3, 5, 7, 9, 11

a₁ = 1 aₙ = 2n – 1

365367: 2n – 1 = 365 2n = 366 n = 183 … 365367 is in the 183rd place of the series sequence

Now let’s check the number follow the number underlined in (1)

0 follow number 13, 1 follow number 35, 2 follow number 57, 3 follow 79

182 numbers should be 0, 1, 2, 3, 4 to n = 183 after 365367

Now this last sequence starts with 369 (a₁) with a difference of 2 from term to term

a₁₈₂ = 2n + 367 = 2 x 182 + 367 = 731