How many grams of H2O are needed to produce 150. g of Mg(OH)2? Mg3N2(s) + 6H2O(l) → 3Mg(OH)2(aq) + 2NH3(g)

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How many grams of H2O are needed to produce 150. g of Mg(OH)2?

Mg3N2(s) + 6H2O(l) → 3Mg(OH)2(aq) + 2NH3(g)

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Approximately 92.67 grams of H2O is required

Explanation:

It’s the easiest way for some people to work backwards.

Given the amount of grams we have already made (for Mg (OH) 2), we can start from there.

In order to get the required gram of H2O we need to know how many moles are actually used in the chemical reaction.

We can obtain this by using the balanced chemical equation to convert from a gram of Magnesium Hydroxide to moles of Magnesium Hydroxide to moles of Water and finally to grams of Water.

** The amu (molar mass) of Mg (OH) 2 is 58.319 g

Step 1 -> 150 g Mg (OH) 2 * = 2.572060563 moles

We can round that up to 2.572 moles of Mg (OH) 2 produced.

Step 2 -> Now we can convert from Mg (OH) 2 moles to H2O moles

We will do this using the balanced chemical equation

2.572 mol Mg (OH) 2 * = 5.144 moles of H2O required

Step 3 -> Now we will convert from moles of H2O (water) to grams

** Using amu (molecular mass)

The molecular mass of water is about 18.015 grams

5.144 moles * = 92.66916 grams of H2O

So, you need about 92.67 grams of H2O