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Two 2.30 cm × 2.30 cm plates that form a parallel-plate capacitor are charged to ± 0.708 nc . part a what is the electric field strength inside the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part b what is potential difference across the capacitor if the spacing between the plates is 1.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer part c what is the electric field strength inside the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. e e = nothing nothing submitrequest answer part d what is the potential difference across the capacitor if the spacing between the plates is 2.00 mm ? express your answer with the appropriate units. v v = nothing nothing submitrequest answer provide feedback next

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A. E = 1.512  times 10 ^ {5}  V.

B. 151.2 V.

C. E = 1.512  times 10 ^ {5}  V.

D. V = 302.4 V.

Solution:

By question:

Plate area of ​​parallel plate capacitors, 2.30  hours 2.30 = 5.29  cm ^ {2} = 5.29  times 10 ^ {- 4}  m ^ {2}

Charge on capacitor plates, Q_ {c} =  pm 0.708  nC =  pm 0.708  times 10 ^ {- 9}  C

Now,

(A) To calculate the strength of the electric field, E when the distance is divided, d = 1.00 mm = 10 ^ {- 3}  m:

E =  frac {Q} { epsilon_ {o} A}

E =  frac {0.708  times 10 ^ {- 9}} {8.85  times 10 ^ {- 12}  times 5.29  times 10 ^ {- 4}} = 1.512  times 10 ^ {5}  N / C

(B) To calculate a potential difference between the plates:

V = Ed = 1.512  times 10 ^ {5}  times 10 ^ {- 3} = 151.2V

(C) The electric field strength when the spacing is 2 mm, ie, 2  times 10 ^ {- 3}  m:

E =  frac {Q} { epsilon_ {o} A}

Since then, the above expression of the electric field shows that it does not depend on the separation distance between the plates so it will remain the same, ie, 1.512  times 10 ^ {5}  V.

(D) Possible difference across capacitor when 2  times 10 ^ {- 3}  m:

V = Ed = 1.512  times 10 ^ {5}  times 2  times 10 ^ {- 3} = 302.4  V.