## THIS USER ASKED ๐

**Would two bits be enough to assign a unique binary number to each vowel in the English language?**

## THIS IS THE BEST ANSWER ๐

Two bits is not enough.

Four bits was enough.

Explanation:

With two bits, only 4 unique binary numbers are available. They are:

00

01

10

11

And since there are 5 lowercase vowel letters and 5 upper vowel letters in English, making a total of 10 vowel letters, two bits will only serve 4 of the 10 letters and therefore are not enough.

With three bits, only 8 unique binary numbers are available. They are:

000

001

010

011

100

101

110

111

So three bits will only serve 8 of the 10 letters so they are not enough.

With four bits, however, there are 16 binary numbers available. They are:

0000

0001

0010

0011

0100

0101

0110

0111

1000

1001

1010

1011

1100

1101

1110

1111

Four bits is more than enough to accommodate the 10 vowel letters in English.

PS: The number of unique binary numbers found in bits is given by;

2โฟ

So;

If we have 3 bits, the number of binary numbers will be unique

2ยณ = 8

If we have 6 bits, the number of binary numbers will be unique

2โถ = 64

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