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In general, which of the following ranks the repulsions indicated from weakest to strongest? lone pair—bonding pair, lone pair—lone pair, bonding pair—bonding pair lone pair—bonding pair, bonding pair—bonding pair, lone pair—lone pair bonding pair—bonding pair, lone pair—bonding pair, lone pair—lone pair lone pair—lone pair, lone pair—bonding pair, bonding pair—bonding pair

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answer: The value of the enthalpy change is -152.80 kj.

solution:

pressure = 1atm, temperature 25 ^ oc= 298 k ) 0 ^ oc = 273kelvins

o_3 + 3no  rightarrow 3no_2,  delta h_ {reaction} =? [/)</p><p>[tex] delta h_ {no} = 90.4kj / mol

 delta h_ {no_2} = 33.85kj / mol

 delta h_ {o_3} = 142.2kj / mol

 delta h_ {reaction} =  sum  delta h_ {products} -  sum  delta h_ {reactants} = 3  times  delta h_ {no_2} - (3  times  delta h_ {no} +  delta h_ { o_3})

 delta h_ {reaction} = 33.85- (90.4 + 142.2) = - 311.85kj / mol

since pressure and temperature are the same in both gases, the number of moles of the two gases can be determined by the ideal gas equation.

v_ {no} = 12.00 l, v_ {o_3} = 8.50 l

pv_ {no} = n_ {no} rt = 1atm  times 12.00 l = n_ {no}  times 0.0821 atml / k mol  times 298 k

n_ {no} = 0.49 mol

pv_ {o_3} = n_ {o_3} rt = 1atm  times 8.50 l = n_ {o_3}  times 0.0821 atml / k mol  times 298 k

n_ {o_3} = 0.34 moles

by reaction any 3 moles react with 1 mol o_3 , then 0.49 mol does not react with  frac {1} {3}  times 0.49 ozone molecules containing 0.16 moles ozone. oh, no limiting reagent and o_3 it is an excessive reagent.

The enthalpy change for the reaction between certain volumes of gases is:

 delta h_ {reaction}  times  text {moles of no} = - 311.85kj / mol  times 0.49 mol = -152.80kj / mol