THIS USER ASKED ๐Ÿ‘‡

How many grams of kbr are required to make 350. ml of a 0.115 m kbr solution?

THIS IS THE BEST ANSWER ๐Ÿ‘‡

0.115 M means that 0.115 moles of KBr are found in a volume of 1000 ml, thus a volume of 350 ml (0.115 ร— 0.35) = 04025 moles
From the formula of moles molarity = molarity ร— volume in liters
1 KBr mole equals 119 g
Thus, the mass = 0.04025 ร— 119 g = 4.79 g