## THIS USER ASKED ๐

**How many grams of kbr are required to make 350. ml of a 0.115 m kbr solution?**

## THIS IS THE BEST ANSWER ๐

0.115 M means that 0.115 moles of KBr are found in a volume of 1000 ml, thus a volume of 350 ml (0.115 ร 0.35) = 04025 moles

From the formula of moles molarity = molarity ร volume in liters

1 KBr mole equals 119 g

Thus, the mass = 0.04025 ร 119 g = 4.79 g