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G- how many grams of f2 gas are there in a 5.00-l cylinder at 4.00 × 103 mm hg and 23°c?

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PV = nRT (4000 Torr) (5 L) = n (62.4 Torr-L / mol-K) (296K) n = 1.08 moles 28 g / mol, 1.08 moles = 30.3 grams your answer is C.30.3 g