THIS USER ASKED 👇
Determine the [oh-] concentration of a 0.741 m koh solution at 25°c.
THIS IS THE BEST ANSWER 👇
Ionized KOH as follows,
KOH → K⁺ + OH⁻
OH tiú concentration is 0.741 M, and calculate your pOH,
pOH = -log [OH⁻]
pOH = -log (0.741)
pOH = 0.130
As well as that,
pH + pOH = 14
pH + 0.130 = 14
pH = 14 – 0.130
pH = 13.87
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