THIS USER ASKED ๐
Ag has an anomalous electron configuration. write the observed electron configuration of ag. express your answer in complete form in order of increasing orbital energy. for example, 1s22s2 should be entered as 1s^22s^2.
THIS IS THE BEST ANSWER ๐
In Silver, the 4d orbitals will be fully filled. This implies that it does not have two electrons in an orbit of 5s. Electronic Cash configuration is:
Ag (47) = 1s ^ 2 2s ^ 2 2p ^ 6 3s ^ 2 3p ^ 6 4s ^ 2 3d ^ 10 4p ^ 6 5s ^ 1 4d ^ 10
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